# lab 6 worksheet

Table 1
m = …… (kg)
M = …… (kg)
Trial
h (m)
V (m/s)
v0-cal (m/s)
v0-given (m/s)
%v0
pi (kg.m/s)
pf (kg.m/s)
Ki (J)
Kf (J)
%K
Ki/Kf – 1
1

2

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3

4

5

Show calculation steps for one trial as an example:

Table 2
m = …… (kg)
v0-given = …… (m/s)
Trial
M (kg)
h (m)
V (m/s)
v0-cal (m/s)
%v0
pi (kg.m/s)
pf (kg.m/s)
Ki (J)
Kf (J)
%K
Ki/Kf – 1
1

2

3

4

5

Table 3
M = …… (kg)
v0-given = …… (m/s)
Trial
m (kg)
h (m)
v (m/s)
v0-cal (m/s)
%v0
pi (kg.m/s)
pf (kg.m/s)
Ki (J)
Kf (J)
Ki/Kf – 1
%K
1

2

3

4

5

Graphs from Excel
(Ki/Kf – 1) vs. v0-calculated

(Ki/Kf – 1) vs. M

(Ki/Kf – 1) vs. 1/m

Conclusions
• Which quantity is conserved in the experiment? Which quantity in your data tables supports your answer?

• Which quantity is not conserved in the experiment? Is the loss amount large relative to the initial value? Show data to prove your affirmation.

• How does the quantity (Ki/Kf – 1) depend on v0, M and m (not depend, linearly or inversely proportional )? Referring to your graphs to affirm your conclusion.

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